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X2+X2=21800
We move all terms to the left:
X2+X2-(21800)=0
We add all the numbers together, and all the variables
2X^2-21800=0
a = 2; b = 0; c = -21800;
Δ = b2-4ac
Δ = 02-4·2·(-21800)
Δ = 174400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{174400}=\sqrt{1600*109}=\sqrt{1600}*\sqrt{109}=40\sqrt{109}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{109}}{2*2}=\frac{0-40\sqrt{109}}{4} =-\frac{40\sqrt{109}}{4} =-10\sqrt{109} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{109}}{2*2}=\frac{0+40\sqrt{109}}{4} =\frac{40\sqrt{109}}{4} =10\sqrt{109} $
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