X2+y2=25y=4

Solution for X2+y2=25y=4 equation:

X2+X2=25X=4

We move all terms to the left:

X2+X2-(25X)=0

We add all the numbers together, and all the variables

2X^2-25X=0

a = 2; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·2·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*2}=\frac{50}{4}
=12+1/2
$