X2+y2=34X+y=2

Solution for X2+y2=34X+y=2 equation:

X2+X2=34X+X=2

We move all terms to the left:

X2+X2-(34X+X)=0

We add all the numbers together, and all the variables

X2+X2-(+35X)=0

We add all the numbers together, and all the variables

2X^2-(+35X)=0

We get rid of parentheses

2X^2-35X=0

a = 2; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·2·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*2}=\frac{70}{4}
=17+1/2
$