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X2+X2=425
We move all terms to the left:
X2+X2-(425)=0
We add all the numbers together, and all the variables
2X^2-425=0
a = 2; b = 0; c = -425;
Δ = b2-4ac
Δ = 02-4·2·(-425)
Δ = 3400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3400}=\sqrt{100*34}=\sqrt{100}*\sqrt{34}=10\sqrt{34}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{34}}{2*2}=\frac{0-10\sqrt{34}}{4} =-\frac{10\sqrt{34}}{4} =-\frac{5\sqrt{34}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{34}}{2*2}=\frac{0+10\sqrt{34}}{4} =\frac{10\sqrt{34}}{4} =\frac{5\sqrt{34}}{2} $
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