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X2+X2=47
We move all terms to the left:
X2+X2-(47)=0
We add all the numbers together, and all the variables
2X^2-47=0
a = 2; b = 0; c = -47;
Δ = b2-4ac
Δ = 02-4·2·(-47)
Δ = 376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{376}=\sqrt{4*94}=\sqrt{4}*\sqrt{94}=2\sqrt{94}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{94}}{2*2}=\frac{0-2\sqrt{94}}{4} =-\frac{2\sqrt{94}}{4} =-\frac{\sqrt{94}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{94}}{2*2}=\frac{0+2\sqrt{94}}{4} =\frac{2\sqrt{94}}{4} =\frac{\sqrt{94}}{2} $
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