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X2-10X-12=63
We move all terms to the left:
X2-10X-12-(63)=0
We add all the numbers together, and all the variables
X^2-10X-75=0
a = 1; b = -10; c = -75;
Δ = b2-4ac
Δ = -102-4·1·(-75)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-20}{2*1}=\frac{-10}{2} =-5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+20}{2*1}=\frac{30}{2} =15 $
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