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X2-10X-40=0
We add all the numbers together, and all the variables
X^2-10X-40=0
a = 1; b = -10; c = -40;
Δ = b2-4ac
Δ = -102-4·1·(-40)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{65}}{2*1}=\frac{10-2\sqrt{65}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{65}}{2*1}=\frac{10+2\sqrt{65}}{2} $
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