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X2-10X-96=0
We add all the numbers together, and all the variables
X^2-10X-96=0
a = 1; b = -10; c = -96;
Δ = b2-4ac
Δ = -102-4·1·(-96)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*1}=\frac{-12}{2} =-6 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*1}=\frac{32}{2} =16 $
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