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X2-14X-12=0
We add all the numbers together, and all the variables
X^2-14X-12=0
a = 1; b = -14; c = -12;
Δ = b2-4ac
Δ = -142-4·1·(-12)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{61}}{2*1}=\frac{14-2\sqrt{61}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{61}}{2*1}=\frac{14+2\sqrt{61}}{2} $
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