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X2-14X-240=0
We add all the numbers together, and all the variables
X^2-14X-240=0
a = 1; b = -14; c = -240;
Δ = b2-4ac
Δ = -142-4·1·(-240)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-34}{2*1}=\frac{-20}{2} =-10 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+34}{2*1}=\frac{48}{2} =24 $
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