X2-16=(x+4)(x-4)

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Solution for X2-16=(x+4)(x-4) equation: 



X2-16=(X+4)(X-4)

We move all terms to the left:

X2-16-((X+4)(X-4))=0

We add all the numbers together, and all the variables

X^2-((X+4)(X-4))-16=0

We use the square of the difference formula

X^2+X^2+16-16=0

We add all the numbers together, and all the variables

2X^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{4}=0$

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