X2-16x=10

Solution for X2-16x=10 equation:

X2-16X=10

We move all terms to the left:

X2-16X-(10)=0

We add all the numbers together, and all the variables

X^2-16X-10=0

a = 1; b = -16; c = -10;
Δ = b2-4ac
Δ = -162-4·1·(-10)
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{74}}{2*1}=\frac{16-2\sqrt{74}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{74}}{2*1}=\frac{16+2\sqrt{74}}{2}
$