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X2-20X+98=0
We add all the numbers together, and all the variables
X^2-20X+98=0
a = 1; b = -20; c = +98;
Δ = b2-4ac
Δ = -202-4·1·98
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{2}}{2*1}=\frac{20-2\sqrt{2}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{2}}{2*1}=\frac{20+2\sqrt{2}}{2} $
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