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X2-22X+96=0
We add all the numbers together, and all the variables
X^2-22X+96=0
a = 1; b = -22; c = +96;
Δ = b2-4ac
Δ = -222-4·1·96
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-10}{2*1}=\frac{12}{2} =6 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+10}{2*1}=\frac{32}{2} =16 $
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