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X2-22X-325=0
We add all the numbers together, and all the variables
X^2-22X-325=0
a = 1; b = -22; c = -325;
Δ = b2-4ac
Δ = -222-4·1·(-325)
Δ = 1784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1784}=\sqrt{4*446}=\sqrt{4}*\sqrt{446}=2\sqrt{446}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{446}}{2*1}=\frac{22-2\sqrt{446}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{446}}{2*1}=\frac{22+2\sqrt{446}}{2} $
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