X2-22x-48=0

Solution for X2-22x-48=0 equation:

X2-22X-48=0

We add all the numbers together, and all the variables

X^2-22X-48=0

a = 1; b = -22; c = -48;
Δ = b2-4ac
Δ = -222-4·1·(-48)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*1}=\frac{48}{2}
=24
$