X2-24x+140=0

Solution for X2-24x+140=0 equation:

X2-24X+140=0

We add all the numbers together, and all the variables

X^2-24X+140=0

a = 1; b = -24; c = +140;
Δ = b2-4ac
Δ = -242-4·1·140
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4}{2*1}=\frac{20}{2}
=10
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4}{2*1}=\frac{28}{2}
=14
$