X2-24x+23=0

Solution for X2-24x+23=0 equation:

X2-24X+23=0

We add all the numbers together, and all the variables

X^2-24X+23=0

a = 1; b = -24; c = +23;
Δ = b2-4ac
Δ = -242-4·1·23
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-22}{2*1}=\frac{2}{2}
=1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+22}{2*1}=\frac{46}{2}
=23
$