X2-26x+168=0

Solution for X2-26x+168=0 equation:

X2-26X+168=0

We add all the numbers together, and all the variables

X^2-26X+168=0

a = 1; b = -26; c = +168;
Δ = b2-4ac
Δ = -262-4·1·168
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*1}=\frac{24}{2}
=12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*1}=\frac{28}{2}
=14
$