X2-2x-(45)2=128

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Solution for X2-2x-(45)2=128 equation:



X2-2X-(45)2=128
We move all terms to the left:
X2-2X-(45)2-(128)=0
We add all the numbers together, and all the variables
X^2-2X-580=0
a = 1; b = -2; c = -580;
Δ = b2-4ac
Δ = -22-4·1·(-580)
Δ = 2324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2324}=\sqrt{4*581}=\sqrt{4}*\sqrt{581}=2\sqrt{581}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{581}}{2*1}=\frac{2-2\sqrt{581}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{581}}{2*1}=\frac{2+2\sqrt{581}}{2} $

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