X2-2x-8=4+2x

Solution for X2-2x-8=4+2x equation:

X2-2X-8=4+2X

We move all terms to the left:

X2-2X-8-(4+2X)=0

We add all the numbers together, and all the variables

X2-2X-(2X+4)-8=0

We add all the numbers together, and all the variables

X^2-2X-(2X+4)-8=0

We get rid of parentheses

X^2-2X-2X-4-8=0

We add all the numbers together, and all the variables

X^2-4X-12=0

a = 1; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·1·(-12)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8}{2*1}=\frac{12}{2}
=6
$