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X2-320X-4=0
We add all the numbers together, and all the variables
X^2-320X-4=0
a = 1; b = -320; c = -4;
Δ = b2-4ac
Δ = -3202-4·1·(-4)
Δ = 102416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{102416}=\sqrt{16*6401}=\sqrt{16}*\sqrt{6401}=4\sqrt{6401}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-4\sqrt{6401}}{2*1}=\frac{320-4\sqrt{6401}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+4\sqrt{6401}}{2*1}=\frac{320+4\sqrt{6401}}{2} $
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