X2-34x+288=0

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Solution for X2-34x+288=0 equation:



X2-34X+288=0
We add all the numbers together, and all the variables
X^2-34X+288=0
a = 1; b = -34; c = +288;
Δ = b2-4ac
Δ = -342-4·1·288
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2}{2*1}=\frac{32}{2} =16 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2}{2*1}=\frac{36}{2} =18 $

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