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X2-39X-106=0
We add all the numbers together, and all the variables
X^2-39X-106=0
a = 1; b = -39; c = -106;
Δ = b2-4ac
Δ = -392-4·1·(-106)
Δ = 1945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1945}}{2*1}=\frac{39-\sqrt{1945}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1945}}{2*1}=\frac{39+\sqrt{1945}}{2} $
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