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X2-3=3X+1
We move all terms to the left:
X2-3-(3X+1)=0
We add all the numbers together, and all the variables
X^2-(3X+1)-3=0
We get rid of parentheses
X^2-3X-1-3=0
We add all the numbers together, and all the variables
X^2-3X-4=0
a = 1; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·1·(-4)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*1}=\frac{-2}{2} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*1}=\frac{8}{2} =4 $
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