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X2-3X=245
We move all terms to the left:
X2-3X-(245)=0
We add all the numbers together, and all the variables
X^2-3X-245=0
a = 1; b = -3; c = -245;
Δ = b2-4ac
Δ = -32-4·1·(-245)
Δ = 989
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{989}}{2*1}=\frac{3-\sqrt{989}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{989}}{2*1}=\frac{3+\sqrt{989}}{2} $
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