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X2-40X-348=0
We add all the numbers together, and all the variables
X^2-40X-348=0
a = 1; b = -40; c = -348;
Δ = b2-4ac
Δ = -402-4·1·(-348)
Δ = 2992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2992}=\sqrt{16*187}=\sqrt{16}*\sqrt{187}=4\sqrt{187}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-4\sqrt{187}}{2*1}=\frac{40-4\sqrt{187}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+4\sqrt{187}}{2*1}=\frac{40+4\sqrt{187}}{2} $
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