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X2-43X+462=0
We add all the numbers together, and all the variables
X^2-43X+462=0
a = 1; b = -43; c = +462;
Δ = b2-4ac
Δ = -432-4·1·462
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-1}{2*1}=\frac{42}{2} =21 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+1}{2*1}=\frac{44}{2} =22 $
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