X2-46x+240=0

Solution for X2-46x+240=0 equation:

X2-46X+240=0

We add all the numbers together, and all the variables

X^2-46X+240=0

a = 1; b = -46; c = +240;
Δ = b2-4ac
Δ = -462-4·1·240
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-34}{2*1}=\frac{12}{2}
=6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+34}{2*1}=\frac{80}{2}
=40
$