X2-48x+540=0

Solution for X2-48x+540=0 equation:

X2-48X+540=0

We add all the numbers together, and all the variables

X^2-48X+540=0

a = 1; b = -48; c = +540;
Δ = b2-4ac
Δ = -482-4·1·540
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-12}{2*1}=\frac{36}{2}
=18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+12}{2*1}=\frac{60}{2}
=30
$