X2-58x+400=0

Solution for X2-58x+400=0 equation:

X2-58X+400=0

We add all the numbers together, and all the variables

X^2-58X+400=0

a = 1; b = -58; c = +400;
Δ = b2-4ac
Δ = -582-4·1·400
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-42}{2*1}=\frac{16}{2}
=8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+42}{2*1}=\frac{100}{2}
=50
$