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X2-5X=5(5-X)
We move all terms to the left:
X2-5X-(5(5-X))=0
We add all the numbers together, and all the variables
X2-5X-(5(-1X+5))=0
We add all the numbers together, and all the variables
X^2-5X-(5(-1X+5))=0
We calculate terms in parentheses: -(5(-1X+5)), so:We get rid of parentheses
5(-1X+5)
We multiply parentheses
-5X+25
Back to the equation:
-(-5X+25)
X^2-5X+5X-25=0
We add all the numbers together, and all the variables
X^2-25=0
a = 1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·1·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*1}=\frac{-10}{2} =-5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*1}=\frac{10}{2} =5 $
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