X2-60x+500=0

Solution for X2-60x+500=0 equation:

X2-60X+500=0

We add all the numbers together, and all the variables

X^2-60X+500=0

a = 1; b = -60; c = +500;
Δ = b2-4ac
Δ = -602-4·1·500
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-40}{2*1}=\frac{20}{2}
=10
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+40}{2*1}=\frac{100}{2}
=50
$