X2-62x+672=0

Solution for X2-62x+672=0 equation:

X2-62X+672=0

We add all the numbers together, and all the variables

X^2-62X+672=0

a = 1; b = -62; c = +672;
Δ = b2-4ac
Δ = -622-4·1·672
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-34}{2*1}=\frac{28}{2}
=14
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+34}{2*1}=\frac{96}{2}
=48
$