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X2-6X+5=3X-13
We move all terms to the left:
X2-6X+5-(3X-13)=0
We add all the numbers together, and all the variables
X^2-6X-(3X-13)+5=0
We get rid of parentheses
X^2-6X-3X+13+5=0
We add all the numbers together, and all the variables
X^2-9X+18=0
a = 1; b = -9; c = +18;
Δ = b2-4ac
Δ = -92-4·1·18
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3}{2*1}=\frac{6}{2} =3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3}{2*1}=\frac{12}{2} =6 $
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