X2-6x+9=(x-3)(x-3)

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Solution for X2-6x+9=(x-3)(x-3) equation: 



X2-6X+9=(X-3)(X-3)

We move all terms to the left:

X2-6X+9-((X-3)(X-3))=0

We add all the numbers together, and all the variables

X^2-6X-((X-3)(X-3))+9=0

We multiply parentheses ..

X^2-((+X^2-3X-3X+9))-6X+9=0



We calculate terms in parentheses: -((+X^2-3X-3X+9)), so:

(+X^2-3X-3X+9)

We get rid of parentheses

X^2-3X-3X+9

We add all the numbers together, and all the variables

X^2-6X+9

Back to the equation:

-(X^2-6X+9)



We add all the numbers together, and all the variables

X^2-6X-(X^2-6X+9)+9=0

We get rid of parentheses

X^2-X^2-6X+6X-9+9=0

We add all the numbers together, and all the variables

=0

X=0/1

X=0

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