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X2-6X-422=0
We add all the numbers together, and all the variables
X^2-6X-422=0
a = 1; b = -6; c = -422;
Δ = b2-4ac
Δ = -62-4·1·(-422)
Δ = 1724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1724}=\sqrt{4*431}=\sqrt{4}*\sqrt{431}=2\sqrt{431}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{431}}{2*1}=\frac{6-2\sqrt{431}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{431}}{2*1}=\frac{6+2\sqrt{431}}{2} $
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