X2-7x-17=(x-3)(x+5)

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Solution for X2-7x-17=(x-3)(x+5) equation: 



X2-7X-17=(X-3)(X+5)

We move all terms to the left:

X2-7X-17-((X-3)(X+5))=0

We add all the numbers together, and all the variables

X^2-7X-((X-3)(X+5))-17=0

We multiply parentheses ..

X^2-((+X^2+5X-3X-15))-7X-17=0



We calculate terms in parentheses: -((+X^2+5X-3X-15)), so:

(+X^2+5X-3X-15)

We get rid of parentheses

X^2+5X-3X-15

We add all the numbers together, and all the variables

X^2+2X-15

Back to the equation:

-(X^2+2X-15)



We add all the numbers together, and all the variables

X^2-7X-(X^2+2X-15)-17=0

We get rid of parentheses

X^2-X^2-7X-2X+15-17=0

We add all the numbers together, and all the variables

-9X-2=0

We move all terms containing X to the left, all other terms to the right

-9X=2

X=2/-9

X=-2/9

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