X2-8x+20=2x-5

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Solution for X2-8x+20=2x-5 equation: 



X2-8X+20=2X-5

We move all terms to the left:

X2-8X+20-(2X-5)=0

We add all the numbers together, and all the variables

X^2-8X-(2X-5)+20=0

We get rid of parentheses

X^2-8X-2X+5+20=0

We add all the numbers together, and all the variables

X^2-10X+25=0

a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{10}{2}=5$

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