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X2-94X+840=0
We add all the numbers together, and all the variables
X^2-94X+840=0
a = 1; b = -94; c = +840;
Δ = b2-4ac
Δ = -942-4·1·840
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-74}{2*1}=\frac{20}{2} =10 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+74}{2*1}=\frac{168}{2} =84 $
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