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X2-9X=5
We move all terms to the left:
X2-9X-(5)=0
We add all the numbers together, and all the variables
X^2-9X-5=0
a = 1; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·1·(-5)
Δ = 101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{101}}{2*1}=\frac{9-\sqrt{101}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{101}}{2*1}=\frac{9+\sqrt{101}}{2} $
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