X2=2(11x-48)

Solution for X2=2(11x-48) equation:

X2=2(11X-48)

We move all terms to the left:

X2-(2(11X-48))=0

We add all the numbers together, and all the variables

X^2-(2(11X-48))=0


We calculate terms in parentheses: -(2(11X-48)), so:

2(11X-48)

We multiply parentheses

22X-96

Back to the equation:

-(22X-96)


We get rid of parentheses

X^2-22X+96=0

a = 1; b = -22; c = +96;
Δ = b2-4ac
Δ = -222-4·1·96
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-10}{2*1}=\frac{12}{2}
=6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+10}{2*1}=\frac{32}{2}
=16
$