X2r-3(4r+1)=5r+27

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Solution for X2r-3(4r+1)=5r+27 equation: 



X2X-3(4X+1)=5X+27

We move all terms to the left:

X2X-3(4X+1)-(5X+27)=0

We multiply parentheses

X2X-12X-(5X+27)-3=0

We get rid of parentheses

X2X-12X-5X-27-3=0

We add all the numbers together, and all the variables

-17X+X2X-30=0

We move all terms containing X to the left, all other terms to the right

-17X+X2X=30

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