X3(2x-7)(3x+1)=(2x-5)(3x+2)

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Solution for X3(2x-7)(3x+1)=(2x-5)(3x+2) equation: 



X3(2X-7)(3X+1)=(2X-5)(3X+2)

We move all terms to the left:

X3(2X-7)(3X+1)-((2X-5)(3X+2))=0

We multiply parentheses ..

X3(+6X^2+2X-21X-7)-((2X-5)(3X+2))=0



We calculate terms in parentheses: -((2X-5)(3X+2)), so:

(2X-5)(3X+2)

We multiply parentheses ..

(+6X^2+4X-15X-10)

We get rid of parentheses

6X^2+4X-15X-10

We add all the numbers together, and all the variables

6X^2-11X-10

Back to the equation:

-(6X^2-11X-10)



We multiply parentheses

6X^5+2X^4-21X^4-7X^3-(6X^2-11X-10)=0

We get rid of parentheses

6X^5+2X^4-21X^4-7X^3-6X^2+11X+10=0

We do not support eXpression: X^5

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