If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X=(2X+27)/5
We move all terms to the left:
X-((2X+27)/5)=0
We multiply all the terms by the denominator
X*5)-((2X+27)=0
Wy multiply elements
5X^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{0}{10}=0$
| 1/2x+23=3x-2 | | 2.x-5=x+3 | | 3(2x-5)-5(x+3)=1 | | 4^x=0.0016 | | 4x-3(-2x+4=((x+6) | | 3.x=54 | | Y=0.40x+140 | | 13x+4=10-3x | | Y+{8+2y}-(3y+5)=5 | | -6x+9=17 | | (0.1)^3x-4=100 | | Y+{8-2y}-(3y+5)=-5 | | 5(2-y)+y=−6 | | 2(x-5+3)+2x=10-8(x+2) | | 2(2a+3)-3(a-2)=3 | | 5x=0,5x+3=2x+3 | | 5x=x÷2+3=2x+3 | | 5x=x÷2+3 | | 2x+3=0,5x+3 | | 8x-5x+155=8x+100 | | x+5/2x-6=7/10 | | -4(m-3)=m-6 | | 10=6x^2-32/54 | | x+(18x/100)=35000 | | 34-2t=2 | | -43=m/6+-51 | | 6c-13=29 | | 3(x)+7=43 | | r/7+27=36 | | t+60/9=9 | | -17+3m=7m+11 | | -j+-66=-22 |