If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X=(3X-2)/(2X+5)
We move all terms to the left:
X-((3X-2)/(2X+5))=0
Domain of the equation: (2X+5))!=0We multiply all the terms by the denominator
X∈R
X*(2X+5))-((3X-2)=0
| 45=2w | | 6+26=n-12 | | 8+5(x-6)=11-6(x-3) | | 3(1z-14)=15 | | 5y+4=-1 | | 1m+11=12 | | 9x÷7=18 | | 16=7+3u | | 9=-6x-2 | | 1-7v=-62 | | -3s+-11=4 | | 5x²+7x-90=0 | | 3(x+2)=3x-27-(x-9) | | 2h+11=-39 | | 18x+5=3x+6 | | |2x=7| | | 15+0.14x=24+0.12x | | x-1/3=2/2x+7 | | 3(2l+4)=63 | | 10x^2+x-54=0 | | 1/(t+3)+2/(t-3)=4 | | 2=-2/9+u | | 0.42-0.33y=3.33-y | | 5(2/x+3)=35 | | 7=-7a-56 | | 0.33333/x=0.01 | | 0.3333/x=1 | | x²-3x+300=0 | | 65=9p+2 | | 6x+3=9x–5 | | 3x+(4+13)=180 | | (w/5)-(13/20)=(w/4) |