X=(4b+1)*3b

Solution for X=(4b+1)*3b equation:

X=(4X+1)*3X

We move all terms to the left:

X-((4X+1)*3X)=0


We calculate terms in parentheses: -((4X+1)*3X), so:

(4X+1)*3X

We multiply parentheses

12X^2+3X

Back to the equation:

-(12X^2+3X)


We get rid of parentheses

-12X^2+X-3X=0

We add all the numbers together, and all the variables

-12X^2-2X=0

a = -12; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-12)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-12}=\frac{0}{-24}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-12}=\frac{4}{-24}
=-1/6
$