X=(4x+3)(4x+3)

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Solution for X=(4x+3)(4x+3) equation: 



X=(4X+3)(4X+3)

We move all terms to the left:

X-((4X+3)(4X+3))=0

We multiply parentheses ..

-((+16X^2+12X+12X+9))+X=0



We calculate terms in parentheses: -((+16X^2+12X+12X+9)), so:

(+16X^2+12X+12X+9)

We get rid of parentheses

16X^2+12X+12X+9

We add all the numbers together, and all the variables

16X^2+24X+9

Back to the equation:

-(16X^2+24X+9)



We add all the numbers together, and all the variables

X-(16X^2+24X+9)=0

We get rid of parentheses

-16X^2+X-24X-9=0

We add all the numbers together, and all the variables

-16X^2-23X-9=0

a = -16; b = -23; c = -9;
Δ = b2-4ac
Δ = -232-4·(-16)·(-9)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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