X=(7x-1)(9x+5)

Solution for X=(7x-1)(9x+5) equation:

X=(7X-1)(9X+5)

We move all terms to the left:

X-((7X-1)(9X+5))=0

We multiply parentheses ..

-((+63X^2+35X-9X-5))+X=0


We calculate terms in parentheses: -((+63X^2+35X-9X-5)), so:

(+63X^2+35X-9X-5)

We get rid of parentheses

63X^2+35X-9X-5

We add all the numbers together, and all the variables

63X^2+26X-5

Back to the equation:

-(63X^2+26X-5)


We add all the numbers together, and all the variables

X-(63X^2+26X-5)=0

We get rid of parentheses

-63X^2+X-26X+5=0

We add all the numbers together, and all the variables

-63X^2-25X+5=0

a = -63; b = -25; c = +5;
Δ = b2-4ac
Δ = -252-4·(-63)·5
Δ = 1885
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{1885}}{2*-63}=\frac{25-\sqrt{1885}}{-126}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{1885}}{2*-63}=\frac{25+\sqrt{1885}}{-126}
$