X=(9x-24)(4x+36)

Solution for X=(9x-24)(4x+36) equation:

X=(9X-24)(4X+36)

We move all terms to the left:

X-((9X-24)(4X+36))=0

We multiply parentheses ..

-((+36X^2+324X-96X-864))+X=0


We calculate terms in parentheses: -((+36X^2+324X-96X-864)), so:

(+36X^2+324X-96X-864)

We get rid of parentheses

36X^2+324X-96X-864

We add all the numbers together, and all the variables

36X^2+228X-864

Back to the equation:

-(36X^2+228X-864)


We add all the numbers together, and all the variables

X-(36X^2+228X-864)=0

We get rid of parentheses

-36X^2+X-228X+864=0

We add all the numbers together, and all the variables

-36X^2-227X+864=0

a = -36; b = -227; c = +864;
Δ = b2-4ac
Δ = -2272-4·(-36)·864
Δ = 175945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-227)-\sqrt{175945}}{2*-36}=\frac{227-\sqrt{175945}}{-72}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-227)+\sqrt{175945}}{2*-36}=\frac{227+\sqrt{175945}}{-72}
$